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化學莫耳數&限量試劑

Jan 11th 2014, 11:24

莫耳數(n)=氣體體積(STP)/22.4
=體積莫耳濃度(M)*體積(L)
是什麼啊 OAO? 不懂欸 ..

還有

N2H4 有4公克與四氧化氮2.3克若完全反應生成氮氣及水,求

(1)何者為限量限量試劑?
2N2H4+N2O4→3N2+4H2O 然後算到這我就不知道要怎麼辦了,英文符號後面的數字都應該要小一點才對但是我不知道怎麼打~

(2)產生氮氣多少莫耳?

(3)若完全反應,僅產生了1.2克的水,則此唪硬的產率為多少%? (N=14)

我想要詳細解釋這些題目~~~快要段考了救救我吧ˊˋ

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